x^2-8x+32=1

Solution for x^2-8x+32=1 equation:

Simplifying
x2 + -8x + 32 = 1

Reorder the terms:
32 + -8x + x2 = 1

Solving
32 + -8x + x2 = 1

Solving for variable 'x'.

Reorder the terms:
32 + -1 + -8x + x2 = 1 + -1

Combine like terms: 32 + -1 = 31
31 + -8x + x2 = 1 + -1

Combine like terms: 1 + -1 = 0
31 + -8x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-31' to each side of the equation.
31 + -8x + -31 + x2 = 0 + -31

Reorder the terms:
31 + -31 + -8x + x2 = 0 + -31

Combine like terms: 31 + -31 = 0
0 + -8x + x2 = 0 + -31
-8x + x2 = 0 + -31

Combine like terms: 0 + -31 = -31
-8x + x2 = -31

The x term is -8x.  Take half its coefficient (-4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
-8x + 16 + x2 = -31 + 16

Reorder the terms:
16 + -8x + x2 = -31 + 16

Combine like terms: -31 + 16 = -15
16 + -8x + x2 = -15

Factor a perfect square on the left side:
(x + -4)(x + -4) = -15

Can't calculate square root of the right side.

The solution to this equation could not be determined.